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fix: Excel_RenameSheet 兼容目录键名 newSheet

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处理器此前只读 newName/name/sheetName，而 Excel_RenameSheet 目录定义
与属性面板使用 newSheet，导致已填写新表名仍报「新 Sheet 名称为空」；
补充别名回归测试
This commit is contained in:
yu 2026-10-28 13:12:32 +08:00
parent ac20d59283
commit 54571eff8d
2 changed files with 9 additions and 1 deletions
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8
src/main/capabilities/office-aliases.test.ts
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@ -50,6 +50,14 @@ describe("common Excel aliases", () => {
await expect(run("Excel_OpenExcel", { filePath: created.path })).resolves.toMatchObject({ path: created.path });
});
it("renames a sheet through the Excel_RenameSheet newSheet key", async () => {
const directory = await mkdtemp(path.join(os.tmpdir(), "rpa-excel-rename-")); dirs.push(directory);
const created = await run("Excel_NewExcel", { filePath: directory, name: "rename-me.xlsx" }) as { path: string };
await expect(run("Excel_RenameSheet", { objExcel: created, sheet: "Sheet1", newSheet: "库存表", isSave: "True" })).resolves.toBeTruthy();
const reopened = await run("Excel_OpenExcel", { filePath: created.path }) as { id: string };
await expect(run("Excel_GetSheetsName", { objExcel: reopened })).resolves.toEqual(["库存表"]);
});
it("writes a range through the Excel_WriteRange catalog keys (objExcel/cellPos/data/isSave)", async () => {
const directory = await mkdtemp(path.join(os.tmpdir(), "rpa-excel-range-")); dirs.push(directory);
const created = await run("Excel_NewExcel", { filePath: directory, name: "range.xlsx" }) as { path: string };

2
src/main/capabilities/office.ts
View File

@ -197,7 +197,7 @@ register(["Excel_GetSheetsName", "Excel_GetSheetNames"], async (_ctx, node, args
register(["Excel_Cs_Rename", "Excel_RenameSheet"], async (_ctx, node, args) => {
const { handle, workbook } = await resolveWorkbook(args, node.id, node.componentId);
const oldName = required(value(args, ["sheet", "oldName"]), "原 Sheet 名称", node.id, node.componentId);
const newName = required(value(args, ["newName", "name", "sheetName"]), "新 Sheet 名称", node.id, node.componentId);
const newName = required(value(args, ["newSheet", "newName", "name", "sheetName"]), "新 Sheet 名称", node.id, node.componentId);
const sheet = sheetOf(workbook, oldName);
sheet.name = newName;
await workbook.xlsx.writeFile(handle.path);