PayrollManagementSystem/backend/tests/unit/test_report_helpers.py
liuwenxin 04a1a0d307 feat(report): 报表四页与打印视图
- 个人绩效明细/部门绩效汇总/业务统计/回款统计四页,路由组「报表统计」order19-22(allowedRoles admin/finance/leader)
- 明细分页页脚全筛选合计;部门汇总成员内联与跨页下钻;业务统计展开回款/台账;回款统计 8 档区间(档位由后端下发)与桶下钻
- 打印视图独立顶层路由(不挂 BasicLayout):公司页眉走 public 端点、循环翻页取全量(2000 行截断提示)、@media print A4 横版每页表头、签字栏
- AppPagination 只派发 page-change/size-change,四页按事件绑定并补初始加载(@change/v-model 不生效的同类缺陷)
- e2e report_flow.py:四页筛选与导出下载、打印视图 window.print 桩断言

Co-Authored-By: Claude Code <noreply@anthropic.com>
2026-10-19 16:33:37 +08:00

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"""报表辅助纯函数与 Excel 模板构建单元测试(M4 ⑤)。
这组用例守的是「不测会静默出错」的三类点:
- 区间分桶边界错一档 → 金额进错桶,但报表仍然「能打开」,没人会发现
- 标签映射漏一个枚举值 → 报表少一类数据或显示英文编码
- 导出模板缺签字栏 / 金额被转 float / 文本公式注入 → 交给财务的签字稿失真
"""
import io
from datetime import date
from decimal import Decimal
from openpyxl import load_workbook
from app.core import report_meta
from app.core.constants import CUSTOMER_TYPES, PRODUCT_CATEGORIES
from app.services import report_export
class Test区间分桶:
"""回款天数 → 8 档区间(含 ≤0 与无天数两个兜底桶)。"""
def test_边界值全部落入正确区间(self):
cases = [
(None, "none"),
(-5, "le0"),
(0, "le0"),
(1, "1-30"),
(30, "1-30"),
(31, "31-60"),
(60, "31-60"),
(61, "61-90"),
(90, "61-90"),
(91, "91-180"),
(180, "91-180"),
(181, "181-360"),
(360, "181-360"),
(361, "361+"),
(1000, "361+"),
]
for days, code in cases:
assert report_meta.bucket_of(days).code == code, f"days={days}"
def test_八档且编码唯一(self):
buckets = report_meta.get_payment_day_buckets()
assert len(buckets) == 8
assert len({b.code for b in buckets}) == 8
class Test标签覆盖:
"""标签键集合必须覆盖业务常量——防常量新增后报表静默少算/显示编码。"""
def test_客户类型标签覆盖全部类型(self):
assert set(report_meta.CUSTOMER_TYPE_LABELS) >= CUSTOMER_TYPES
def test_产品类别标签覆盖常量与混合业务(self):
assert set(report_meta.PRODUCT_CATEGORY_LABELS) >= PRODUCT_CATEGORIES
assert "mixed" in report_meta.PRODUCT_CATEGORY_LABELS
def _build(code: str, rows: list[dict], buckets: dict | None = None) -> bytes:
return report_export.build_workbook(
code=code,
title="测试报表",
filters="统计月份 2026-10",
rows=rows,
summary=None,
buckets=buckets,
template_version="V1.0",
operator_name="admin",
company_name="衍水集团",
)
def _sheet_text(content: bytes) -> str:
workbook = load_workbook(io.BytesIO(content))
return "\n".join(
str(cell.value)
for row in workbook.active.iter_rows()
for cell in row
if cell.value is not None
)
def _personal_row(**overrides) -> dict:
row = {
"business_no": "YW001",
"ship_date": date(2026, 10, 1),
"receipt_date": date(2026, 10, 20),
"payment_days": 20,
"product_category": "municipal_water",
"customer_type": "personal",
"role_name": "营销员",
"rate_text": "88/9000",
"weight_r": 100,
"performance_amount": Decimal("39.11"),
"payable_amount": Decimal("39.11"),
}
row.update(overrides)
return row
class TestExcel模板:
"""导出稿是交给财务复核与领导签字的,结构缺失等同于没有模板。"""
def test_页眉标题签字栏齐全(self):
text = _sheet_text(_build("personal-detail", [_personal_row()]))
assert "衍水集团" in text
assert "测试报表" in text
assert "统计月份 2026-10" in text
assert "模板版本:V1.0" in text
assert "财务复核" in text
assert "领导签字" in text
def test_空数据不炸且给提示行(self):
text = _sheet_text(_build("personal-detail", []))
assert "本筛选条件无数据" in text
assert "财务复核" in text
def test_金额为数值单元格且两位格式(self):
# openpyxl 写入 Decimal 后读回为 int/float(Excel 单元格本身是数值),
# 这里断言「是数值而非文本」+ 显示格式;计算精度在服务层 Decimal 侧保证
content = _build("personal-detail", [_personal_row()])
workbook = load_workbook(io.BytesIO(content))
sheet = workbook.active
amount_cells = [
cell
for row in sheet.iter_rows()
for cell in row
if isinstance(cell.value, (int, float))
and Decimal(str(cell.value)) == Decimal("39.11")
]
assert amount_cells, "未找到金额数值单元格(Decimal 被转成了文本?)"
assert amount_cells[0].number_format == "#,##0.00"
def test_合计行等于明细之和且标签只出现一次(self):
rows = [
_personal_row(performance_amount=Decimal("10.00"), payable_amount=Decimal("10.00")),
_personal_row(performance_amount=Decimal("5.50"), payable_amount=Decimal("5.50")),
]
content = _build("personal-detail", rows)
workbook = load_workbook(io.BytesIO(content))
cells = [cell for row in workbook.active.iter_rows() for cell in row]
values = [
Decimal(str(cell.value))
for cell in cells
if isinstance(cell.value, (int, float))
]
assert Decimal("15.50") in values
# 「合计」标签只写一次(写满每个文本列是回归缺陷)
assert sum(1 for cell in cells if cell.value == "合计") == 1
def test_文本公式注入被前置单引号(self):
evil = "=HYPERLINK(\"http://evil\")"
content = _build("personal-detail", [_personal_row(business_no=evil)])
workbook = load_workbook(io.BytesIO(content))
values = [
cell.value
for row in workbook.active.iter_rows()
for cell in row
if isinstance(cell.value, str)
]
assert any(value.startswith("'=") for value in values), "公式注入未转义"
def test_回款统计附两个维度对比sheet(self):
buckets = {
"by_customer_type": [
{
"label": "个人户",
"receipt_amount": Decimal("100.00"),
"performance_amount": Decimal("1.00"),
"payable_amount": Decimal("1.00"),
"ledger_count": 1,
}
],
"by_product_category": [],
}
content = _build(
"payment-stats",
[
{
"label": "1-30 天",
"receipt_amount": Decimal("100.00"),
"receipt_count": 1,
"performance_amount": Decimal("1.00"),
"payable_amount": Decimal("1.00"),
"ledger_count": 1,
}
],
buckets=buckets,
)
workbook = load_workbook(io.BytesIO(content))
assert workbook.sheetnames == ["回款统计", "客户类型对比", "产品类别对比"]
def test_业务统计状态转中文(self):
rows = [
{
"business_no": "YW001",
"business_date": date(2026, 10, 1),
"customer_name": "测试客户",
"owner_personnel_name": "张三",
"status": 2,
"total_sale_amount": Decimal("100.00"),
"total_ship_amount": Decimal("100.00"),
"total_received_amount": Decimal("100.00"),
"performance_amount": Decimal("1.00"),
"payable_amount": Decimal("1.00"),
}
]
text = _sheet_text(_build("business-stats", rows))
assert "已完成" in text